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^2/3-2Y^2/3-3=0
We multiply all the terms by the denominator
-2Y^2-3*3+^2=0
We add all the numbers together, and all the variables
-2Y^2=0
a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$Y=\frac{-b}{2a}=\frac{0}{-4}=0$
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